*Post by uglyvan**Post by Spalls Hurgenson*On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

*Post by uglyvan*roll one d6;

roll a second d6;

if both d6s roll the same number then stop Rolling dice;

as long as dice rolled bring different values, keep Rolling one die;

stop Rolling dice as soon as you get two similar values;

count the number of dice rolled;

it represents your stat Rank;

1st d6: 6

2nd d6: 3

3rd d6: 4

4th d6: 3

2nd d6 = 4th d6

stop.

4 dice rolled means you have a stat Rank of Good;

Rank name

7 epic ( olympic )

6 superb

5 excellent

4 good

3 typical

2 mediocre

the DnD score is 3 times the stat Rank

Rank Score

7 ---- 21

6 ---- 18

5 ---- 15

4 ---- 12

3 ----- 9

2 ----- 6

repeat the process for each of your basic stats

for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.

Still don't see the point; it seems unduly complicated for no good

purpose (and limits you to only a fixed number of attribute points;

nobody is going to get an attribute of 13 using this system, for

instance).

But at least it isn't just random digital gibberish.

Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have

gone mad.

Nice day for it.

for example, if one good mathematics user would print the probabilities for ranks of 2 to 7

like in 2d6 bring 6 possibilities out of 36 combos

unfortunately I quit school one year before Baccalauréat, so I didn't learn probabilities along with integrals

:)

On 2d6 there's always a 1 in 6 chance of both dice rolling the same

number, there's really no point in doing that, you can just roll a d6, and

stop if you roll a 1 and have the exact same chance.

So there's a 16.66% chance of stopping at 1. Since the chances of each

come out of the remaining chances overall each is 1/6 of what's left, so on

the 2nd roll it's 13.88 (16.66% of the remaining 83.33%), on the third

it's 11.67% (16.66% of the remaining 69.44%).

4 = 9.64%

5 = 8.03%

6 = 6.69%

7 = 5.58%

8 = 4.65%

etc. You get below 1% at 17, and the possibilities go to infinity.

The mean is 6 - so that's what your average human would be.

I'm not really math inclined, but I like knowing probabilities. Also I

was just figuring out this same problem 2 days ago for how long it would

take to actually find a secret door with a party in 1e.

I prefer my 27-25-23 +2 Organic method.

https://sites.google.com/site/justisaursdd/tar-pit-dugout/justisaurs27-25-23abilityscoregeneration

- Justisaur